NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections

NCERT Solutions for Class 11 Maths Chapter 11 Exercise 11.1

Ex 11.1 Class 11 NaQuestion 1:

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Ex 11.1 Class 11 Maths Question 10:

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Ex 11.1 Class 11 Maths Question 11:
Find the equation of the circle passing through the points (2, 3) and (-1, 1) and whose centre is on the line x – 3y – 11 = 0.
Solution:
The equation of the circle is,
(x – h)2 + (y – k)2 = r2 ….(i)
Since the circle passes through point (2, 3)
∴ (2 – h)2 + (3 – k)2 = r2
⇒ 4 + h2 – 4h + 9 + k2 – 6k = r2
⇒ h2+ k2 – 4h – 6k + 13 = r2 ….(ii)
Also, the circle passes through point (-1, 1)
∴ (-1 – h)2 + (1 – k)2 = r2
⇒ 1 + h2 + 2h + 1 + k2 – 2k = r2
⇒ h2 + k2 + 2h – 2k + 2 = r2 ….(iii)
From (ii) and (iii), we have
h2 + k2 – 4h – 6k + 13 = h2 + k2 + 2h – 2k + 2
⇒ -6h – 4k = -11 ⇒ 6h + 4k = 11 …(iv)
Since the centre (h, k) of the circle lies on the line x – 3y-11 = 0.
∴ h – 3k – 11 = 0 ⇒ h -3k = 11 …(v)
Solving (iv) and (v), we get
h =  and k = 
Putting these values of h and k in (ii), we get

⇒  ⇒ 
Thus required equation of circle is
⇒ 
⇒ 
⇒ 4×2 + 49 – 28x + 4y2 + 25 + 20y = 130
⇒ 4×2 + 4y2 – 28x + 20y – 56 = 0
⇒ 4(x2 + y2 – 7x + 5y -14) = 0
⇒ x2 + y2 – 7x + 5y -14 = 0.
Ex 11.1 Class 11 Maths Question 12:

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Ex 11.1 Class 11 Maths Question 13:

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Ex 11.1 Class 11 Maths Question 14:

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Ex 11.1 Class 11 Maths Question 15:

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NCERT Solutions for Class 11 Maths Chapter 11 Exercise 11.2

Ex 11.2 Class 11 Maths Question 1:

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Ex 11.2 Class 11 Maths Question 8:

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Ex 11.2 Class 11 Maths Question 9:

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Ex 11.2 Class 11 Maths Question 10:

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Ex 11.2 Class 11 Maths Question 11:

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Ex 11.2 Class 11 Maths Question 12:

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NCERT Solutions for Class 11 Maths Chapter 11 Exercise 11.3

Ex 11.3 Class 11 Maths Question 1:

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Ex 11.3 Class 11 Maths Question 8:

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Ex 11.3 Class 11 Maths Question 9:

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Ex 11.3 Class 11 Maths Question 10:

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Ex 11.3 Class 11 Maths Question 11:

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Ex 11.3 Class 11 Maths Question 12:

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Ex 11.3 Class 11 Maths Question 13:

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Ex 11.3 Class 11 Maths Question 14:

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NCERT Solutions for Class 11 Maths Chapter 11 Exercise 11.4

Ex 11.4 Class 11 Maths Question 1:

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Ex 11.4 Class 11 Maths Question 8.
Vertices (0, ±5), foci (0, ±8)
Solution:
Vertices are (0, ±5) which lie on x-axis. So the equation of hyperbola in standard form

Ex 11.4 Class 11 Maths Question 9.
Vertices (0, ±3), foci (0, ±5)
Solution:
Vertices are (0, ±3) which lie on x-axis. So the equation of hyperbola in standard form

Ex 11.4 Class 11 Maths Question 10:

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Ex 11.4 Class 11 Maths Question 11:

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Ex 11.4 Class 11 Maths Question 12:

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Class 11 Maths NCERT Solutions – Miscellaneous Questions

Miscellaneous Exercise Class 11 Maths Question 1:

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Miscellaneous Exercise Class 11 Maths Question 8:

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